2x^+5x=x^2+36

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Solution for 2x^+5x=x^2+36 equation: 



2x^+5x=x^2+36

We move all terms to the left:

2x^+5x-(x^2+36)=0

We add all the numbers together, and all the variables

7x-(x^2+36)=0

We get rid of parentheses

-x^2+7x-36=0

We add all the numbers together, and all the variables

-1x^2+7x-36=0

a = -1; b = 7; c = -36;
Δ = b2-4ac
Δ = 72-4·(-1)·(-36)
Δ = -95
Delta is less than zero, so there is no solution for the equation

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